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On Tue, 12 May 1998, Bihari Gabor wrote:
> Poor guy. That is about 10-100 tons of iridium.
Sorry, I forgot a "thousand" from the number.
That is cca. 10-100 thousand tons.
> On Sun, 10 May 1998, Earl Wood wrote:
> > James R. Cunningham wrote:
> > > > At 08:28 PM 5/6/98 -0700, Earl Wood wrote:
> > > > > I would like to know if anyone has calculated the amount of
> > > > > Iridium
> > > > >needed to
> > > > >cover the entire earths surface , at the depth associated with the K C
> > > > >boundary ? and if so does anyone have these figures , or a reference
> > > > >that would be available to Joe citizen ?
> > >
> > > This is from memory, so is untrustworthy. I believe I read some years
> > > ago that assuming iridium concentrations typical of other meteors, it
> > > would have taken an asteroid about 5-8 miles in diameter to contain the
> > > iridium needed to match measured amounts at the K-T boundary.
> > > Best wishes,
> > > Jim
> > In my efforts to find the answer to this question , I looked at the
> > Alvarez work on this question and their figures state.......common
> > meteorites
> > have iridium of about 500 parts per billion, they calculated that the world
> > wide iridium anomaly at about ( 0.5 million tons)to introduce that much
> > iridium
> > would require a meteorite 10 kilometers in diameter ,
> > slightly larger than the nucleus of Halley's comet . This was taken from
> > their
> > paper in
> > Science magazine. Just a refresher in case you are interested. Thanks for
> > your
> > post
> > I really appreciate any help I can Get..
> > Earl Wood
> > email@example.com
- Re: iridium
- From: Bihari Gabor fiz5 9711 <firstname.lastname@example.org>